How to solve this problem

When completely dissolved, 3.2 g of copper in h. HNO3 released 3 g of nitric oxide. What is the mass fraction of NO2 output from the theoretical possible?
There are 6 answers
Common Miracle
Common Miracle
Answered on January 20, 2015 15:31
You must first withdraw the reaction. Nitric oxide is N02. Сu + 4HN03 -> Cu (N03) 2 + 2N02 + 2Н20 Then decide the formulas
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best_or_nothing
best_or_nothing
Answered on January 20, 2015 15:59
Julia, good afternoon! I can only suggest the following. There is little that I remember, therefore. You write the reaction, then calculate the formulas for the number of released N02, then translate into grams - you get the theoretically possible.
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best_or_nothing
best_or_nothing
Answered on January 20, 2015 16:00
Reaction equation: Cu + 4HNO3 = Cu (NO3) 2 + 2NO2 + 2H2O
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best_or_nothing
best_or_nothing
Answered on January 20, 2015 16:07
1. Find the amount of substance si. The number of things. = Mass of substance / molar mass = 3.2 / 64 = 0.05 mol. 2. According to the equation of the reaction, the quantity of a gas substance is twice as large (a factor of two before NO2), hence the quantity of a gas substance is 0.05 * 2 = 0.1 mol.
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best_or_nothing
best_or_nothing
Answered on January 20, 2015 16:40
3. Find the theoretical mass of the gas. Mass = quantity of substances. * Molar mass = 0.1 mol * 46 g / mol = 4.6 g. 4.

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